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d-średnica
r=d:2
r=2cm:2
r=1
P=4(pi)r2
P=4(pi)(1cm)2
P=4(pi)1cm
P=4(pi)cm2
V=4/3(pi)r3
V=4/3(pi)1cm2
V=4/3(pi)1cm
V=4/3(pi)cm3
P=πr²=π*1²=π≈3,14cm²
obw L=2πr=2*π*1=2π≈6,28cm
b) dlugosc przekatnej kwadratu to jest srednica okregu
d=a√2=2√2
P=πr²=π*(2√2)²=4π≈12,56cm²
L=2πr=4√2π≈17,77cm