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k1 : k2
1 : 4
phi.2.r : phi.2.r
2r : 2r
r : r
jadi r1 = 1 dan r2 = 4
luas = phi.r²
karena r ny dh tau jdi
L1 : L2
phi.r² : phi.r²
r² : r²
1² : 4²
1 : 16
# nomer 10
sudut ACB
= sudut AOB / 2
= 84/2
= 42
# nomer 11
sudut B = sudut A
sudut A = 60
karena membentuk segitiga maka jumlh sudt nya 180.
A + B + AOB = 180
60 + 60 + AOB = 180
120 + AOB = 180
AOB = 60
karena berpelurus maka
180 = AOB + BOC
180 = 60 + BOC
BOC = 180 - 60
BOC = 120
#nomer 12
cari dlu sudut CDA
CDA = 88/2 = 44
krna berpelurus jdi
180 = CDA + CDB
180 = 44 + CDB
CDB = 136
segitiga slalu jmlh sdtny 180. maka
180 = 20 + 136 + B
B = 180 - 156
B = 24
# nomer 14
panjang busur
= (sudut/360) x kllng
= 60/360 . phi.2r
= 1/6 . 3,14 . 2. 30
= 31,40
# nomer 15
luas juring
= sudut/360 . luas
= 105/360 . 22/7 . 14²
= 7/24 . 616
= 179,67
# nomer 21
gak tau