Kulę ołowianą o średnicy 20cm przetopino na kulki o średnicy 10 razy mniejszej.Oblicz ile kulek otrzymano.
d1 = 20 cm
r1 = 10 cm
d2 = 20cm/10 = 2 cm
r2 = 1 cm
n = ?
V kuli = (4/3)TTr^3
V1 = (4/3)TTr1^3 = (4/3)TT*(10cm)^3 = 4000TT/3 cm3
V2 = (4/3)TTr2^3 = (4/3)TT*(1cm)^3 = 4TT/3 cm3
n = V1/V2 = 4000TT/3 : 4T/3
n = 1000
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Odp.Otrzymano 1000 kulek.
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d1 = 20 cm
r1 = 10 cm
d2 = 20cm/10 = 2 cm
r2 = 1 cm
n = ?
V kuli = (4/3)TTr^3
V1 = (4/3)TTr1^3 = (4/3)TT*(10cm)^3 = 4000TT/3 cm3
V2 = (4/3)TTr2^3 = (4/3)TT*(1cm)^3 = 4TT/3 cm3
n = V1/V2 = 4000TT/3 : 4T/3
n = 1000
=======
Odp.Otrzymano 1000 kulek.