Question

Kuis thn ajaran baru:
(i.) 1 + 1 = .....
(ii.) 2 + 2 = .....
(iii) 3 + 3 = .....
(iv.) 4 + 4 = .....

(v.) Jika (ln9)÷(ln3) = ᵃlog25, a = ....

Answer 1

Jawaban:

i.) 1 + 1 = 2

(ii.) 2 + 2 = 4

(iii.) 3 + 3 = 6

(iv.) 4 + 4 = 8

(v.) (ln9)÷(ln3) = ᵃlog25

ln(9) ≈ 2.197

ln(3) ≈ 1.099

2.197 ÷ 1.099 = ᵃlog(25)

10^2 = 100 = 25.

log(25) = 2

2.197 ÷ 1.099 = ᵃ * 2

2.197 ÷ 1.099 ÷ 2 = ᵃ

1.995 ≈ ᵃ

a ≈ 1.995.

Answer 2

Verified answer

Penjelasan dengan langkah-langkah:

Soal apa ini

i. 1+1 = 2

ii. 2+2 = 4

iii. 3+3 = 6

iv. 4+4 = 8

v. mager pakai latex a nya ganti n :D

In(9) ÷ In(3) = ⁿlog25

=> In(a)÷In(n) = ⁿlog a

³log 9 = ⁿlog 25

³log 3² = ⁿlog 25

2.³log 3 = ⁿlog 25

2.1 = ⁿlog 25

2 = ⁿlog 25

n² = 25

n = √25

n = 5

a = 5