Jawaban:
C
Penjelasan dengan langkah-langkah:
panjang s1 = √(8²+6²)
= √(64+36)
= √100
= 10 cm
panjang s2 = √(8² + [21-6]²)
= √(64+225)
= √289
= 17 cm
Keliling = 2 x (s1 + s2)
Keliling = 2 x (10 + 17)
Keliling = 2 x 27
Mencari panjang sisi 1 dan sisi 2
s1= √8² + 6²
s1 = √(8×8)+(6×6)
s1=√64 + 36
s1= √100 cm
s1 = 10 cm.
s2= √ 8²(21-6 )
s2 = √(8×8)+(15²))
s2= √64 + (15×15)
s2 = √64+ 225
s2 = √289 cm
s2 = 17 cm
K = 2 × ( d1 + d2)
K= 2 × (s1+ s2) ---->
K= 2 × ( 10 + 17 cm)
K= 2 × (27 cm)
K= 54 cm.
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Jawaban:
C
Penjelasan dengan langkah-langkah:
panjang s1 = √(8²+6²)
= √(64+36)
= √100
= 10 cm
panjang s2 = √(8² + [21-6]²)
= √(64+225)
= √289
= 17 cm
Keliling = 2 x (s1 + s2)
Keliling = 2 x (10 + 17)
Keliling = 2 x 27
Keliling = 54 cm
•°• Penyelesaian Soal•°•
Mencari panjang sisi 1 dan sisi 2
s1= √8² + 6²
s1 = √(8×8)+(6×6)
s1=√64 + 36
s1= √100 cm
s1 = 10 cm.
s2= √ 8²(21-6 )
s2 = √(8×8)+(15²))
s2= √64 + (15×15)
s2 = √64+ 225
s2 = √289 cm
s2 = 17 cm
K = 2 × ( d1 + d2)
K= 2 × (s1+ s2) ---->
K= 2 × ( 10 + 17 cm)
K= 2 × (27 cm)
K= 54 cm.
Opsi c.