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Verified answer
Materi: Geometri AnalitikJawaban D
Verified answer
Perhatikan gambarLuas AEGF = 36 cm^2
s^2 = 36
s = 6 => AG = GF
Luas GHLB = 25 cm^2
s^2 = 25
s = 5 => GB = GH
HF = GF - GH = 6 - 5 = 1 => HF = FJ = 1 cm
Luas HFJI = 1^2 = 1 cm^2 =============> luas persegi terkecil
EJ = EF + FJ = 6 + 1 = 7 cm => EJ = ED = 7 cm
Luas EDKJ = 7^2 = 49 cm^2 ===========> luas persegi terbesar
Jadi perbandingan luas persegi terkecil dan terbesarnya 1 : 49
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