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Dik : lim r==> 3/2 rkutub (1/r - 1/rkutub + ω²r²/2GM) = 03/2 rkutub (1/r - 1/rkutub + ω²r²/2GM) = 0
1/(3/2 rkutub) - 1/rkutub + ω²2,25rkutub²/2GM = 0
2/3 rkutub - 3/ 3rkutub + ω²2,25rkutub²/2GM = 0
ω²2,25rkutub²/2GM = 1/3rkutub
ω² = 2GM / 6,75rkutub³
ω = √(8/27) √(GM/rkutub³)
C
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Materi: Matematika AstronomiPembahasan di gambar :v
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