Kubus ABCD.EFGH mempunyai panjang rusuk 12 cm. Titik M dan titik N masing-masing terletak di tengah rusuk EF dan rusuk EH. Jarak garis MN terhadap garis BD adalah
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Kubus
r = 12 cm
M tengah EF
N tengah EH
O tengah ABCD
P tengah MN
P' tengah AO
Jarak garis MN terhadap garis BD
= OP
= √(PP'² + P'0²)
= √(r² + (1/4 r√2)²)
= √(r² + 2/16 r²)
= √((16 + 2)/16 r²)
= √(18/16 r²)
= 3/4 r√2
= 9√2 cm