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•R1=8ohm
•R2=6ohm
•R3=3ohm
•E=12V
•r=0
ditanya:
•kuat arus(I)
penyelesaian:
-menghitung Rp
jadi R total=8 ohm+2 ohm =10 ohm
jadi I=E/R+r
I=12v/10 ohm+ 0 ohm
I=1,2 A
semoga membantu^•^