Kąt ostry trapezu prostokątnego o podstawach długości 24 i 12 ma miarę 82 stopni. Oblicz pole tego trapezu.
a=24 [j]
b=12 [j]
alfa=82*
x=a-b=24-12=12
h/x=tg alfa
h=x*tg82*
tg 82*=7,1154
h=12*7,1154
h=85,3848 [j]
P=(a+b)/2 *h
P=(24+12)/2 *85,3848=18*85,3848
P=1 536,9264 [j^2]
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a=24 [j]
b=12 [j]
alfa=82*
x=a-b=24-12=12
h/x=tg alfa
h=x*tg82*
tg 82*=7,1154
h=12*7,1154
h=85,3848 [j]
P=(a+b)/2 *h
P=(24+12)/2 *85,3848=18*85,3848
P=1 536,9264 [j^2]