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d=2mm
r=1mm=0,1cm
V kropli = 4/3 * π *0,1cm³
Vk= 4/3*0,001*π
Vk=4/3000π
Vk =1/750π cm³
d=6cm
r=3cm
Vw = πr² *H
Vw=π9*8
Vw=72π cm³
ilosc kropel -> Vw/Vk
Vw/Vk = 72π/ 1/750π = 54000π kropli -> dokładnie
Vw/Vk ≈ 54 000 *3,14 ≈ 169560 kropli
Pozdrawiam! :)