Question

a) 1/2 x [(-1)^8 + {-1)^8] = b) (-3 1/3)^3 x 0,3^4-(-1/2)^3 x (1 1/3)^2 = c) (1 1/3 )^3 (-3 3/4)^2 : 3 - (1/3)^2 = d) (-0,3)^2 : 0,1 - 0,2^3 x (2 1/2)^2 e)(-0,1)^4 x 20^3 + (1 1/2)^3 : (-0,3)^2 = Legenda: ^ potęga / kreska ułamkowa x znak mnożenia wymagane rozpisanie zadania niestety :(

Answer 1

a/

1/2x[(-1)⁸+(-1)⁸]=1/2·[(-1)⁸(1+1)]=1/2·1·2=1

 

b/  (-3 ⅓)³·0,3⁴-(-/2)³·(1⅓)²=(-10/3)³·(3/10)⁴-(-4/3)²=-100/27·81/1000-16/9=                           

      3/10-16/9=27/90-160/90=- 133/90.

 

c/  (1⅓)³·(-3¾)²:3-(⅓)²=(4/3)³·(-15/4)² : 3 -1/9=64/27·225/16·1/3-1/9=4/27·225·1/3-1/9=

     900/81-1/9= 100/9-1/9=99/9=11

 

d/  (-0,3)²:0,1-0,2³·(2 1/2)²=(-3/10)²:1/10-(2/10)³·(5/2)²=9/100·10/1-8/1000·25/4=9/10-2/40=

     36/40-2/40=34/40=17/20

 

e/ (-0,1)⁴·20³+(1 1/2)³:(-0,3)²=(-1/10)⁴·8000+ (3/2)³:(-3/10)²=1/1000·8000 +27/8:9/100=

     8+27/8·100/9=8+75/2=16/2+75/2=91/2=45 1/2