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c=kb+b+2k
c=k(b+2)+b
c-b=k(b+2)
(c-b)/(b+2)=k
f=k+1/k+a
f(k+a)=k+1
fk+fa=k+1
fk-k=1-fa
k(f-1)=1-fa
k=(1-fa)/(f-1)
i = a/2 + 2/k |*2
2i = a + 4/k |*k
2ik = ak + 4
2ik-ak = 4
k(2i-a)=4
k=4/(2i-a)