To będzie w dużym nawiasie ( 1+1/3+1/27 4+4/49-4/343 ) 80808080 a) 182x(--------------- : ----------------- ) x -------------- ( 2+2/3+2/27 1+1/49-1/343 ) 91919191
985x654654 b)------------------------------- 327x137137+137+327327 LEGENDA: ( ( =to wszystko to duży nawias (
/ kreska ułamkowa
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------- kreska ułamkowa
justa1234
Zapiszę tak ,jak zrozumiałam; a) 182[(1+1/3+1/27)/(2+2/3+2/27):(4+4/49-4/343)/(1+1/49-1/343)]x(80808080)/(91919191)= 182[(1+9/27+1/27)/(2+18/27+2/27):(4+28/343)/(1+7/343-1/343)]x(80808080)/(91919191)= 182[(37/27)/(74/27):(1396/343)/(349/343)]x(80808080)/(91919191)= 182[(37/27)x(27/74):(1396/343)x(343/349)]x(80808080)/(91919191)= 182[37/74:1/4]x(80808080)/(91919191)= 182[37/74x4/1]x(80808080)/(91919191)= 182[2]x(80808080)/(91919191)= 364x(80808080)/(91919191)= 4x(80808080)/(1010101)= =80
b) 985x654654 ________________________= 327x137137+137+327327
985x2002 __________= 1x464601
1971970:464601= =4,24
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sloven
W zadaniu a) tu jest błąd: 182[37/74:1/4]x(80808080)/(91919191)=
a)
182[(1+1/3+1/27)/(2+2/3+2/27):(4+4/49-4/343)/(1+1/49-1/343)]x(80808080)/(91919191)=
182[(1+9/27+1/27)/(2+18/27+2/27):(4+28/343)/(1+7/343-1/343)]x(80808080)/(91919191)=
182[(37/27)/(74/27):(1396/343)/(349/343)]x(80808080)/(91919191)=
182[(37/27)x(27/74):(1396/343)x(343/349)]x(80808080)/(91919191)=
182[37/74:1/4]x(80808080)/(91919191)=
182[37/74x4/1]x(80808080)/(91919191)=
182[2]x(80808080)/(91919191)=
364x(80808080)/(91919191)=
4x(80808080)/(1010101)=
=80
b)
985x654654
________________________=
327x137137+137+327327
985x2002
__________=
1x464601
1971970:464601=
=4,24