a) 5 - 1/3 (9x-3)=4x+13
b) 3x+2/(kreska ułamowa pod całym) pod kreską x+1 = 2x+4/(kreska ułamkowa pod całym) pod kreską 4x-1 | *24x+1
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a)
5 - 1/3 (9x-3)=4x+13
5-3x+1=4x+13
-7x=7
x=1
b)
A co to na samym końcu |*24x+1??
(3x+2)/(x+1)=(2x+4)/(4x-1)
(x+1)(2x+4)=(3x+2)(4x-1)
2x²+4x+2x+4=12x²-3x+8x-2
-10x²+x+6=0
Δ=1²-4*(-10)*6
Δ=1+240
Δ=241
√Δ=√241
x₁=(-1-√241)/(2*(-10))
x₁=(-1-√241)/(-20)
x₁=(1+√241)/20
x₂=(-1+√241)/(2*(-10))
x₂=(-1+√241)/(-20)
x₂=(1-√241)/20