Zapisz w prostszej postaci :
a) 12xy do potęgi 2 / 4
b) 5a*2a do potęgi 2 / 20
*- razy
/ - kreska ułamkowa .
Dziękuje :*
a)
(12xy) ^2/4 = (12xy)^1/2 =
b)(5a*2a)^2/20=(5a*2a)^1/10=
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a)
(12xy) ^2/4 = (12xy)^1/2 =
b)(5a*2a)^2/20=(5a*2a)^1/10=![\sqrt[10]{(5a*2a)} = \sqrt[10]{(10a^{2})} = \sqrt[9]{(10a)} \sqrt[10]{(5a*2a)} = \sqrt[10]{(10a^{2})} = \sqrt[9]{(10a)}](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7B%285a%2A2a%29%7D+%3D+%5Csqrt%5B10%5D%7B%2810a%5E%7B2%7D%29%7D+%3D+%5Csqrt%5B9%5D%7B%2810a%29%7D+)