koefisien muai panjang tembaga 0,000017/K.
pertambahan panjang sebuah balok tembaga disebabkan oleh 10
°C menjadi 30
°C. jika panjang awal 5,0 mm. adalah?
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Lo = 5 mm
Δt = 30°C-10°C=20°C
α = 0,000017/°C
L = Lo x (1+αxΔt)
= 5 x (1+0,000017x20)
= 5 x (1,000017x20)
= 5 x 20,00034
= 100,0017 mm = 1,7 mm
Δt = t1-t0= 30°-10°=20°
L₀ = 5,00 mm
L₁ = ?
L₁=L₀×(1+α×Δt)
L₁=5,00mm×(1+17×10⁻⁶×20°)
L₁=5,00mm×1,00034
L₁=5,0017
gatau bener gatau salah :)