korzystając ze wzoru:
cos (180⁰ - α) = - cos α
oblicz :
*cos 120 ⁰
*coś 150 ⁰
*cos 135 ⁰
*cos 180 ⁰
Prosze o pełne rozwiązania
Dzieki z góry. :)
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cos ( 180⁰ - α ) = - cos α
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cos 120⁰ = cos (180⁰ - 60⁰) = - cos 60⁰ = - 1/2
cos 150⁰ = cos ( 180⁰ - 30⁰ ) = - cos 30⁰ = - √3/2
cos 135⁰ = cos (180⁰ - 45⁰ ) = - cos 45⁰ = - √2/2
cos 180⁰ = cos ( 180⁰ - 0⁰ ) = - cos 0⁰ = - 1
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