m ukladu= m kolarza + m roweru= 60+20=80 kg
F= 0,2kN=200N
F=ma
a=F:m= 200:80=2,5 m/s²
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m ukladu= m kolarza + m roweru= 60+20=80 kg
F= 0,2kN=200N
F=ma
a=F:m= 200:80=2,5 m/s²