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- Gaya
saya ikuti lambangnya seperti "coret-coret" pada gambar
m₂ = 5 kg μ₂ = 0,1
m₁ = 10 kg μ₁ = 0,2
g = 10 m/s²
F = 45 N
a = __ ?
Gaya gesek antara balok kecil dengan balok besar
fg₂ = μ₂ N₂
= μ₂ m₂ g
= 0,1 · 5 · 10
= 5 N
Gaya gesek antara balok besar dengan bidang alas
fg₁ = μ₁ N₁₂ kedua balok menekan bidang alas
= μ₂ (m₁ + m₂) g
= 0,2 · (5 + 10) · 10
= 30 N
Tegangan tali pada m₂
∑F = m₂ a
T - fg₂ = 0 [m₂ diam]
T = fg₂
T = 5 N ← jawaban
Percepatan m₁
∑F = m₁ a
F - fg₁ - fg₂ = m₁ a
45 - 30 - 5 = 10 a
10 = 10 a
a = 1 m/s² ← jawaban