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mSO3 = 32u + 48 u = 80 u
Zawartość tlenu to 48 u:
80u - 100%
48u - x (%)
x = 48 *100% /80= 60 %
Zawartość siarki to
100% - 60%= 40%.
b) Siarczek glinu
mAl2S3 = 2*27u + 3*32u = 54u + 96u = 150u
Zawartość glinu:
150u - 100%
54u - x (%)
x = 54*100% /150 =36 %
Zwartość siarki:
100% - 36% = 64%
M SO3 = 32 + 3*16 = 80
siarka:
32/80 = 0,4
0,4*100% = 40%
tlen: 100%-40% = 60%
b) siarczku glinu
M Al2S3 = 2*27 + 3*32 = 150
glin:
54/150 = 0,36
0,36 *100% = 36%
tlen: 100%-36% = 64%
SO3
32u + 3* 16u = 80u
80u - 100%
32u - x
x=3200:80
x=40% - siarka
tlen 100%-40%=60%
Siarczek glinu
Al2S3
2*27u+3*32u=54u+96u=150u
150u - 100%
54u - x
x=5400:150
x= 36% glin
100%-36%=64% - siarka