Question

Kka tolong bantuin ya

Answer 1

Verified answer

1. c. bromin, kalium, karbon
2. c. Mg(OH)2
3. b. kalium hipoklorit
4. c. tembaga (II) hidroksida
5. d. h2c2o4
6. e. cac2o4
7. c. 32
8. d. avogadro
9. d. dalton
10. n NO3 = 9,03x10²²/6,02x10²³=1,5x10^-1
v NO3 = 0,15 x 22,4 = 3,36 liter (C)
11. persen H = 6,77%
C: 40/12 = 3,33
O: 53,23/16 = 3,33
H: 6,77/1 = 6,77
C: H: O = 3,33 : 6,77 : 3,33 = 1:2:1
rumus empiris senyawa = CH2O (D)

Answer 2

1. Jawaban C.
Br : bromin
K : kalium
C : karbon

2. Jawaban C.
Mg2+ + 2 OH- ---> Mg(OH)2

3. Jawaban B.
KClO2 : kalium klorit
KClO3 : kalium klorat
KClO4 : kalium perklorat

4. Jawaban C.
Cu2+ + 2 OH- ----> Cu(OH)2

5. Jawaban D.
a. asam sulfat
b. asam silikat
c. asam karbonat
e. asam sulfit

6. Jawaban E.
CaC2O4 : kalsium oksalat

7. Jawaban C.
(NH4)2SO4: 2×14 + 8×1 + S + 4×16 = 132

8. Jawaban D.
sesuai dgn hukum Avogadro

9. Jawaban C.
sesuaibdgn hukum perbandingan gas Gay-Lussac

10. Jawaban C.
9.03×10^22/6.02×10^23 x 22.4 = 3.36 L

11. Jawaban D
C ÷ O ÷ H = 40/12 ÷ 53.23/16 ÷ 6.77/1
= 3.3 ÷ 3.3 ÷ 6.77
= 1 ÷ 1 ÷ 2
R.E = CH2O

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