Penjelasan:
CH3COOH 0,01 M
Ka = 10^-5
[H+] = √Ka . M
[H+] = √(10^-5 . 0,01)
[H+] = √10^-7
[H+] = 10^-3,5
PH = -log H+
PH = -log 10^3,5
PH = 3,5
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Verified answer
Penjelasan:
CH3COOH 0,01 M
Ka = 10^-5
[H+] = √Ka . M
[H+] = √(10^-5 . 0,01)
[H+] = √10^-7
[H+] = 10^-3,5
PH = -log H+
PH = -log 10^3,5
PH = 3,5