KIMIA... !! (tolong) berapa gram masing-masing zat terlarut yang terdapat dalam : A). 100 mL larutan HCL yang pH-nya 2 B). 200 mL larutan NaOH yang pH-nya 13
berapa pH larutan campuran berikut? A). 250 mL HNO₃ 0,1 M + 250 mL air B). 100 mL HCL 0,1 M + 150 mL HCL 0,2 M terima kasih...
Dzaky111
1.a. pH = 2 ---> [H⁺] = 10⁻² M [HCl] = [H⁺] = 10⁻² M n.HCl = [HCl] x V = 10⁻² x 0,1 = 10⁻³ mol m.HCl = n x Mr = 10⁻³ x 36,5 = 0,0365 gram b. pH = 13 ---> pOH = 1 ---> [OH⁻] = 10⁻¹ M [NaOH] = [OH⁻] = 10⁻¹ M n.NaOH = [NaOH] x V = 10⁻¹ x 0,2 = 2 x 10⁻² mol m.NaOH = n x Mr = 2 x 10⁻² x 40 = 80 x 10⁻² = 0,8 gram 2.a. M₂ x V₂ = M₁ x V₁ M₂ x 500 = 0,1 x 250 M₂ = 0,05 M = 5 x 10⁻² M pH = -log 5 x 10⁻² = 2 - log 5 b. Mc = (M₁V₁ + M₂V₂)/(V₁+V₂) = (0,1 x 100 + 0,2 x 150)/(100 + 150) = (10 + 30)/250 = 40/250 = 0,16 M = 16 x 10⁻² M pH = -log 16 x 10⁻² = 2 - log 16
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ravdha
Itu yg nomor 2 a kenapa V2 nya 500ml? Sedangkang di soal 250ml?
[HCl] = [H⁺]
= 10⁻² M
n.HCl = [HCl] x V
= 10⁻² x 0,1
= 10⁻³ mol
m.HCl = n x Mr
= 10⁻³ x 36,5
= 0,0365 gram
b. pH = 13 ---> pOH = 1 ---> [OH⁻] = 10⁻¹ M
[NaOH] = [OH⁻]
= 10⁻¹ M
n.NaOH = [NaOH] x V
= 10⁻¹ x 0,2
= 2 x 10⁻² mol
m.NaOH = n x Mr
= 2 x 10⁻² x 40
= 80 x 10⁻²
= 0,8 gram
2.a. M₂ x V₂ = M₁ x V₁
M₂ x 500 = 0,1 x 250
M₂ = 0,05 M
= 5 x 10⁻² M
pH = -log 5 x 10⁻²
= 2 - log 5
b. Mc = (M₁V₁ + M₂V₂)/(V₁+V₂)
= (0,1 x 100 + 0,2 x 150)/(100 + 150)
= (10 + 30)/250
= 40/250
= 0,16 M
= 16 x 10⁻² M
pH = -log 16 x 10⁻²
= 2 - log 16