Question

Kimia nih broh caranya ?

Answer 1

Tb = 100,26⁰C
Kf = 1,86
Kb = 0,52

ΔTb = Tb - Tb⁰
ΔTb = 100,26 - 100
ΔTb = 0,26⁰C

ΔTb = Kb x m
0,26 = 0,52 x m
m = 0,5 molal

ΔTf = Kf x m
ΔTf = 1,86 x 0,5
ΔTf = 0,93

Tf = Tf°-ΔTf
Tf = 0 - 0,93
Tf = -0,93°C

Jadi, larutan tersebut akan membeku pada suhu -0,93°C (Jawaban B)