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m = 50 gram = 0,05 kg
T0 = 20 C
T = 100 C
c = 4.200 J/KgC
dit : Q ?
dijwb :
Q = m x c x ΔT
= 0,05 x 4.200 x (100-20)
= 0,05 x 4.200 x 80
= 16.800 J
= 16,8 KJ
t1 = 20'C = 293 K
t2 = 100'C = 373 K
c = 4200 J/kg
Dit : Q = .....?
peny : Q = m c ΔT
Q = 0,05. 4200. (373 - 293)
Q = 16.800 kJ