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m=2kg
T0=28°C
T=100
c=4200K/kg°C
Ditanya : Q?
Jawab :
Q=m x c x ΔT
Q=2 x 4200 x (100-28)
Q=8400 x 72
Q=604800 J = 604,8 kJ
= 2 kg . 4.200J/kg⁰C . 72 ⁰C
= 604800 J
= 604,8 KJ