Oblicz, ile energii nalezy dostarczy bryle lodu o masie 2kg i temperaturze -10*C, aby zamienic go w wode o temperaturze 10*C? Cieplo topnienia lodu wynosi: 340 000 J/kg, cieplo wlasciwe lodu wynosi: 2100 J/kg* C cieplo wlasciwe wody wynosi: 4200 J/ kg*C.
hanecka
M = 2 kg t₁ = -10 C t₂ = 0 C t₃ = 10 C Q = Q₁ + Q₂ + Q₃ Q = m* cl * Δt₁ + m*ct + m * cw *Δt₂ Q = m{ cl * [ 0 C - (-10 C) ] + ct + cw * ( 10 C - 0 C ) } Q = 2 kg * [ 2100 J/kg * C * 10 C + 340000 J/kg * 4200 J/kg * C * 10 C ] Q = 2 kg * 403000 J/kg Q = 806000 J = 806 kJ
t₁ = -10 C
t₂ = 0 C
t₃ = 10 C
Q = Q₁ + Q₂ + Q₃
Q = m* cl * Δt₁ + m*ct + m * cw *Δt₂
Q = m{ cl * [ 0 C - (-10 C) ] + ct + cw * ( 10 C - 0 C ) }
Q = 2 kg * [ 2100 J/kg * C * 10 C + 340000 J/kg * 4200 J/kg * C * 10 C ]
Q = 2 kg * 403000 J/kg
Q = 806000 J = 806 kJ