2) diketahui:
m = 500 g = 0,5 kg
t1 = 20°C
Q = 100 kal = 100 x 4,2
= 4.200 J
C = 4.200 J/kg°c
ditanya:
t2
jawab:
Q = m . c . Δt
Δt = Q / m . c
t2 - t1 = Q / m . c
t2 - 20 = 4.200 / 0,5 x 4.200
t2 - 20 = 4.200 / 2.100
t2 - 20 = 2
t2 = 2 + 20
t2 = 22° C
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2) diketahui:
m = 500 g = 0,5 kg
t1 = 20°C
Q = 100 kal = 100 x 4,2
= 4.200 J
C = 4.200 J/kg°c
ditanya:
t2
jawab:
Q = m . c . Δt
Δt = Q / m . c
t2 - t1 = Q / m . c
t2 - 20 = 4.200 / 0,5 x 4.200
t2 - 20 = 4.200 / 2.100
t2 - 20 = 2
t2 = 2 + 20
t2 = 22° C