Tolong Dong!!
air sebanyak 400 kg bersuhu 10°C dimsasukan tembaga 100 kg dengan suhu 60°C. berapakah suhu campuran bila diketahui kalor jenis air 4200J/kg°C dan kalor jenis tembaga 1,2 J/kg°C.
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m.c.(T1-T) =m.c.(T-T2)
100.1.2.(60-T)=400.4200.(T-10)
120(60-T)=168000.(T-10)
720-120T=168000T-1680000
168000T+120T=720+1680000
169120T=1680720
T =1680720/168120
T=9,997