Air bermassa 20 kg bersuhu 20°C dicampur dengan 10 kg air bersuhu 80°C. jika kalor jenis air 4200 J/kg°C, hitunglah: a. kalor yg dilepas air 10 kg b. kalor yg diterima air 20kg c. suhu akhir campuran berdasarkan azas Black
mevansutantop4i826
Qlepas = qterima m c Δt = m c Δt 20 . 4200 . (tc-20) = 10 . 4200 . (80-tc) 2tc-40 = 80-tc 3tc = 120 tc =40 derjat
m c Δt = m c Δt
20 . 4200 . (tc-20) = 10 . 4200 . (80-tc)
2tc-40 = 80-tc
3tc = 120
tc =40 derjat
qlepas
10.4200.80-40 = 4200.60 =252000
qterima
20.4200.40-20= 8400.20=168000kalor