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m= 2 kg
t1=20°C
Q=84.000 J
c=4.200 J/kg°C
Ditanya: t2=....?
Jawab:
Q=m.c.Δt
Δt= Q/m.c
t2-t1 =84.000/2 x 4.200
t2-20 = 84.000/8.400
t2-20 =10
t2 =20+10
t2 =30°C