Air 0,5 kg pd suhu 20°c dpanaskan hingga jd uap air yg suhunya 110°c. jika kalor jenis air 4186 j/kg°c, kalor jenis uap air 2010 j/kg°c dan bsr kalor uap air 22,6×10pangkat5 j/kg, ttntukan bnyaknya kalor yg dperlukan
6ilbert
Q1 = m . c . ΔT = 0,5 . 4186 . (100 - 20) = 167440 Joule = 167,44 kJ Q2 = m . U = 0,5 . 22,6 . 10⁵ = 1130000 Joule = 1130 kJ Q3 = m . c . ΔT = 0,5 . 2010 . (110 - 100) = 10050 Joule = 10,05 kJ
= 0,5 . 4186 . (100 - 20)
= 167440 Joule
= 167,44 kJ
Q2 = m . U
= 0,5 . 22,6 . 10⁵
= 1130000 Joule
= 1130 kJ
Q3 = m . c . ΔT
= 0,5 . 2010 . (110 - 100)
= 10050 Joule
= 10,05 kJ
Q total = 167,44 + 1130 + 10,05
= 1307,49 kJ