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ΔT = T akhir - T awal = 100 - 20 = 80
Q = m.c.ΔT
Q = 0,25 . 4200 . 80
Q = 8.400
2) Q = m. cL
Q = 2. 336.000
Q = 672.000
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Diketahui :
m = 250 gram = 0,25 kg
ΔT = 100 - 20°C = 80°C
c = 4200J/kg°c
Ditanyakan : Q....?
Penyeleseaian :
Q = m c ΔT
= 0,25 . 4200. 80
= 84000 J
= 84 KJ
2.
Diketahui :
m = 2 kg
L = 336.000J/kg
Ditanyakan : Q....?
Penyelesaian :
Q = m L
= 2 kg . 336000 J/kg
= 672000 J
= 672 kJ
3.
Diketahui :
m = 1 kg
ΔT = 80°C
c = 4200j/kg
U = 2.260.000j/kg.
Ditanyakan : Q...?
Jawab :
Q1 = m c ΔT
= 1 . 4200 . 80
= 336000 J
= 336KJ
Q2 = m x U
= 1 x 2.260.000
= 2.260.000 J
= 2.26 KJ
Q tatal = Q1 + Q2
= 336 + 2.26
= 338,26 KJ