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m=250g= 0,25kg
Cw= 4200J/kg/*stC
T= 20stC
Tk=100tC
deltaT= Tk-T
deltaT=80stC
Q= 0,25kg*4200J/kg*stC*80stC= 84000J = 84kJ.
Odp.: Zużyję 84kJ energii.
m 0,25kg
t1 20c
t2 100c
cw 4200 J
delta T 80
cp 2258000
q=0,25*4200*80 kg j c
q=84000j
zuzyjesz 84000j energi
ΔE = m * ΔT * c
ΔE = 0,25kg * 20 stopniC * 4200 J/kg * stopień Celsjusza
ΔE = 21000 J