Jika 10 Kg es 0°C ditambahkan pada 2 kg Uap 100°C, suhu air campuran adalah... (kalor lebur es 335 x 10³ J/Kg, kalor didih air 2200 x 10³ J/Kg, dan kalor jenis air 4190 J/Kg. K)
a). 0°C
b). 23°C
c). 28°C
d). 40°C
e). 50°C
a). 0°C
b). 23°C
c). 28°C
d). 40°C
e). 50°C
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Verified answer
ΔE = Q - W, Q = W = 0 insulatedΔE = 0
ΔU + ΔEp + ΔEk = 0, ΔEk = ΔEp = 0
ΔU = 0
ΔU_es + ΔU_uap = 0
ΔU_es = - ΔU_uap
m_es * [Hl_es + C*(T-0)] = m_es * [ Hl_uap + C*(100-T) ]
10*(335+10*4,19*T) = 2*(2260 + 4,18* (100-T)
5*(335+4,19*T) = 2260 + 4,19* (100-T)
1675 + 20,95 T = 2260 + 419 - 4,19 T
T = 39,93 deg. C ~ 40°C(D)