Jawaban:
Penjelasan:
Diketahui
m=500 gram = 0,5 kg
Suhu awal (t₀) = 20⁰ C
Q=10.000 joule
c = 1000 j/kg ⁰c
Ditanya
tₐ = ...
Jawab
Q = m.c.∆ t
∆ t = Q / (m.c)
∆ t = 10.000 J / (0,5 kg. 1000 j/kg ⁰c)
= 10.000 J / (500 j/⁰c)
= 20 ⁰c
∆ t = tₐ - t₀
20 = tₐ - 20
20 + 20 = tₐ
40⁰ c = tₐ
Suhu akhir menjadi 40⁰ C
Demikian
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Jawaban:
Kalor
Penjelasan:
Diketahui
m=500 gram = 0,5 kg
Suhu awal (t₀) = 20⁰ C
Q=10.000 joule
c = 1000 j/kg ⁰c
Ditanya
tₐ = ...
Jawab
Q = m.c.∆ t
∆ t = Q / (m.c)
∆ t = 10.000 J / (0,5 kg. 1000 j/kg ⁰c)
= 10.000 J / (500 j/⁰c)
= 20 ⁰c
∆ t = tₐ - t₀
20 = tₐ - 20
20 + 20 = tₐ
40⁰ c = tₐ
Suhu akhir menjadi 40⁰ C
Demikian
Semoga membantu dan bermanfaat!