Pada pemanasan perak sebanyak 4 kg diberikan kalor sebanyak 460.000 j. Jika suhu yang tercapai 560 derajat C dan kalor jenis perak 230 j/kg derajat C,tentukan suhu awalnya!
yeahhhnarry
M = 4kg Q = 460.000 j T2 = 560'C c = 230 j/kg'C
T1=?
Q= m.c. delta T 460.000 = 4. 230. delta T 460.000/920 = delta T 500'C = delta T
Ryaade
Q = m x c x Δt 460000 = 4 x 230 x (t2-t1) 460000 = 4 x 230 x (560-t1) 460000 = 920 x (560-t1) 460000 : 920 = 560-t1 500 = 560-t1 t1 = 560-500 t1 = 60
Q = 460.000 j
T2 = 560'C
c = 230 j/kg'C
T1=?
Q= m.c. delta T
460.000 = 4. 230. delta T
460.000/920 = delta T
500'C = delta T
delta T = T2-T1
500 = 560 - T1
500-560 = -T1
60'C =T1
suhu awal 60'C
semoga membantu x
460000 = 4 x 230 x (t2-t1)
460000 = 4 x 230 x (560-t1)
460000 = 920 x (560-t1)
460000 : 920 = 560-t1
500 = 560-t1
t1 = 560-500
t1 = 60