Air sebanyak 2kg. dipanaskan menggunakan kompor dengan kalor sebesar 420kj.jika CA=4.200j/kg derajat celcius dan suhu awal 25 derajat celcius suhu akhir air setalah dipanaskan adalah?
liliput01
Diket: m = 2kg Q = 420 kJ = 420000 J c air = 4200 j/kg'c t1 = 25'c Dit: suhu akhir (t2)....? Δt = Q/mxc Δt = 420000/2x4200 Δt = 420000/8400 Δt = 4200/84 Δt = 50'C , Δt = t2 - t1 t2 = Δt + t1 t2 = 50'c + 25'c t2 = 75'C suhu akhir = 75'C
m = 2kg
Q = 420 kJ = 420000 J
c air = 4200 j/kg'c
t1 = 25'c
Dit: suhu akhir (t2)....?
Δt = Q/mxc
Δt = 420000/2x4200
Δt = 420000/8400
Δt = 4200/84
Δt = 50'C
,
Δt = t2 - t1
t2 = Δt + t1
t2 = 50'c + 25'c
t2 = 75'C
suhu akhir = 75'C