Question

1. air sebanyak 1 liter (masa jenis air) 1000 kg/m kubik) dipanaskan dengan energi 84000 joule dengan kalor jenis air 4200 joule/kg derajat celcius. bila sebelum dipanasi suhu air 10 derajat celcius, tentukan suhu akhirnya?
please buat pr besok

Answer 1

M = 1 liter
q = 84.000 joule
cair = 4.200 j/kg
suhu = (x-10)
q = m . cair . suhu
84.000 = 1 . 4.200 . (x-10)
(x-10) = 84.000/4.200
x = 2 + 10
x = 12

Answer 2

Diket:
Volume air = 1 liter = 0,001 m^3
massa jenis air = 1000 kg/m^3
Kalor jenis air (c air) = 4200 j/Kg
Kalor yg diterima (Q) = 84000 J
t1 = 10'c
Ditanya: t2..........?
Jawab:
massa air = massa jenis x volume
m = 1000 x 0,001
m = 1
 
at = Q/m.c
at = 84000/1x4200
at = 20'c

at = t2 - t1
t2 = at + t1
t2 = 20 + 10
t2 = 30'c

jadi suhu akhir adalah 30'c