Question

10 kg besi 120 derajat C dicelupkan ke dalam 250 gr air 10 derajat C. berapakah suhu campuran jika Cbesi 460 J/kg derajat C?

beserta caranya

Answer 1

Dik:
Massa besi/m = 10 kg
= 10.000 g
Suhu besi/T = 120°C
C besi = 460 J/kg
= 460.000 J/g

Massa air= 250 gram
Suhu air = 10°C
C air= 4,2 Joule/gram°C

Dit:


TC=?

(MCdelta T)besi= (MCdeltaT)air
10000.460.000(120°-Tc)=250.1,2(10-Tc)

46.10^8(120°-Tc)= 300(10-Tc)
552.10^9-46Tc=3000-300Tc
552.10^9-46Tc-3000+300Tc=0
552.10^9-3000+254 TC=0
254Tc= -551999997000
Tc= - 2173228334.6457°C

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