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to = 20°C
Q = 180 kJ
= 180 . 1000 J
= 180000 J
c = 900 J/kg °C
Ditanyakan : t₁ (to + Δt)
Penyelesaian : Δt = Q : (m . c)
= 180000 : (2 . 900)
= 180000 : 1800
= 100°C
t₁ = to + Δt
= 20 + 100
= 120°C
180000=2.900.t2-t1
180000=1800.(t2-20)
180000=1800t2-36000
1800x =180.000+36.000
1800x = 216.000
x = 216.000/1800
x =120
jadikan yg terbaik