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180.000J = 2.900.(ta-20)
dit :ta ?
180.000J = 1.800(ta-20)
100 = ta-20
ta = 120 derajat c
m= 2 kg
t(awal)= 20⁰C
Q= 180 kj= 180.000 j
c= 900 j/kg⁰C
Ditanya :
t(akhir) ?
Jawab :
Q= m × c × Δt
Q= m × c × (t(akhir) - t(awal)
180.000= 2 × 900 × t(akhir) - 20
180.000= 1.800 × t(akhir) - 20
180.000/1.800= t(akhir) - 20
100= t(ahir) - 20
100 + 20= t(akhir)
t(akhir)= 100 + 20
t(akhir)= 120
Jadi, suhu akhir alumunium tersebut adalah 120⁰C.