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diketahui
• m = 300 gr= 0,3 kg
• t awal = -10°C
• t akhir = 40°C
• C es = 2100 J/kg °C
• C air = 4200 J/kg °C
ditanya Q?
jawab
Q es
= m x c x ∆t
= 0,3 x 2100 x ( 0 - ( -10 ))
= 0,3 x 2100 x 10
= 6300 J
Q air
= m x c x ∆t
= 0,3 x 4200 x ( 100 - 0)
= 0,3 x 4200 x 100
= 126000 J
Q total
= 6300 + 126000
= 132300 J