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m= 0,5 kg
Q= 20 kJ --> 20×1000= 20000 joule
t₁= 20 °C
C= 0,093 J/kg°C
Dit:
t₂= ...?
Penye:
t₂= Δt+t₁
Δt= Q/(m×C)
Δt= 20000/(0,5×0,093)
Δt= 20000/0,0465
Δt= 430107,53
t₂= 430107,53+20
t₂= 430127,53 °C
Q = 20 kJ ⇒ 20 × 1000= 20000 joule
t₁ = 20 °C
c = 0,093 J/kg°C
Ditanya = t₂..?
Jawab = Δt = Q/(m×c)
= 20000/(0,5×0,093)
= 20000/0,0465
= 430107,53
t₂ = t₂ + t₁
= 430107,53+20
= 430127,53 °C