Question

Kerjakan Tugas Di Bawah Ini​

Answer 1

[tex]\sqrt{3}\times\sqrt{20}\times\frac{1}{\sqrt{500} }[/tex]

sifat akar:

[tex]\sqrt{a} \times\sqrt{b}=\sqrt{a\times b}[/tex]

[tex]\frac{\sqrt{a} }{\sqrt{b} } =\sqrt{\frac{a}{b} }[/tex]

[tex]\frac{\sqrt{20\times3} }{\sqrt{500} }=\frac{\sqrt{60} }{\sqrt{500} } =\sqrt{\frac{60}{500} } =\sqrt{\frac{3}{25} } =\frac{\sqrt{3} }{\sqrt{25} } =\frac{\sqrt{3} }{5 }[/tex]

[tex](4-3\sqrt3)(4+5\sqrt3)[/tex]

menggunakan metode perkalian FOIL:

(a+b)(c+d) = ac + ad + bc + bd

[tex](4-3\sqrt3)(4+5\sqrt3)=(4\times4)+(4\times5\sqrt3)-(4\times3\sqrt3)-(3\sqrt3 \times5\sqrt3)[/tex]

[tex](4-3\sqrt3)(4+5\sqrt3)=16+20\sqrt3-12\sqrt3-45=-29+8\sqrt3[/tex]