Question

Kerjakan soal nomor 5

Answer 1

AE = rusuk kubus = 4 cm
EG = diagonal bidang = 4√2 cm

Anggap terdapat titik P di tengah-tengah FH, maka :

AP = √(4²+ ((4√2)/2)²)
= √(4² + (2√2)²)
= √(16 + 8)
= √24
= 2√6 cm

sin a = depan/miring
= ((4√2)/2) / (2√6)
= (2√2)/(2√6)
= √2/√6
= √(2/6)
= √(1/3)
= 1/√3
= (1/3) √3
= C.