Keliling segitiga ABC adalah 145 cm. jika panjang sisi AB= (X +8) cm. sisi BC=(2X-5)cm dan sisi ac = (2x+2)cm, maka panjang sisi-sisian tersebut secara berurutan adalah .... tolong dijawab beserta caranya ya..
darmawan1998
Kll = AB + BC + AC 145 = x + 8 + 2x - 5 + 2x + 2 145 = 5x + 5 5x = 145 - 5 5x = 140 x = 28
jadi panjang AB = x + 8 = 28 + 8 = 36 cm panjang BC = 2x - 5 = 2(28) - 5 = 56 - 5 = 51 cm panjang AC = 2x + 2 = 2(28) + 2 =56 + 2 = 58 cm
ValvaAlifia
K = AB + BC + AC 145 = (x + 8) + (2x - 5) + (2x + 2) 145 = 5x + 5 145 - 5 = 5x 140 = 5x x = 28
Panjang sisi AB = (x + 8) = 28 + 8 = 36 cm Panjang sisi BC = (2x - 5) = (2 × 28) - 5 = 56 - 5 = 51 cm Panjang sisi CA = (2x + 2) = (2 × 28) + 2 = 56 +2 = 58 cm
145 = x + 8 + 2x - 5 + 2x + 2
145 = 5x + 5
5x = 145 - 5
5x = 140
x = 28
jadi
panjang AB = x + 8 = 28 + 8 = 36 cm
panjang BC = 2x - 5 = 2(28) - 5 = 56 - 5 = 51 cm
panjang AC = 2x + 2 = 2(28) + 2 =56 + 2 = 58 cm
145 = (x + 8) + (2x - 5) + (2x + 2)
145 = 5x + 5
145 - 5 = 5x
140 = 5x
x = 28
Panjang sisi AB = (x + 8) = 28 + 8 = 36 cm
Panjang sisi BC = (2x - 5) = (2 × 28) - 5 = 56 - 5 = 51 cm
Panjang sisi CA = (2x + 2) = (2 × 28) + 2 = 56 +2 = 58 cm