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31,4 = 3,14d
d = 31,4/3,14
d = 10
r = d/2
r = 10/2
r = 5
t = √(s²-r²)
t = √(13²-5²)
t = √(169-25)
t = √144
t = 12
S=13cm
π=3,14
dit: t..?
jawab: pertama cari dulu jarijari kerucut dgn rumus=>
K.alas=2.π.r
31,4 =2.3,14.r
31,4 =6,28.r
31,4 : 6,28 = r
5 cm = r
maka t=√s²-r²
=√13²-5²
=√169-25
=√144
=12 cm