Kedalam 500 gram air di larutkan 17,4 gram k2so4=174. maka titik beku larutan adalah .... bantu jawab ya, ... yg lengkap jawab nya diketahui= ditanya= jawab=
Ramsyahnovaldy
Diketahui = massa = 17,4 gram Mr = 174 mol = massa/Mr = 17,4/174 = 0,1 mol
massa air = 500 gram = 0,5 kg vant hoff = 3 Kf = 1,86
ditanyakan = titik beku ? jawaban = ...
Delta Tb = mol/massa air x Kf x i = 0,1/0,5 x 1,86 x 3 = 1,116 derajad celcius
massa = 17,4 gram
Mr = 174
mol = massa/Mr = 17,4/174 = 0,1 mol
massa air = 500 gram = 0,5 kg
vant hoff = 3
Kf = 1,86
ditanyakan = titik beku ?
jawaban = ...
Delta Tb = mol/massa air x Kf x i
= 0,1/0,5 x 1,86 x 3
= 1,116 derajad celcius
Titik beku = 0 - 1,116
= - 1,116 derajad celcius